Well.....each of the tie-breakers is weighted the same...no problem there.
Rober posted on Monday, October 13, 2008 9:36 PM
Well.....each of the tie-breakers is weighted the same...no problem there.
However, I want to use tie-breaker #1 ONLY to break the initial tie. Then,
if there is still a tie then I wish to employ tie-breaker #2...similar for
the use of #3. The formula suggested would, mathematically, make it possible
for two of the values to still be the same; as happened when utilized for the
current data shown. The individual tie-breakers shown across each row
should, ideally, be used only for the reference total....otherwise there
might be some cross contamination of the final results. Certainly I can do
this procedure manually but I'd really love to have a built-in function to do
the same; show my new rank vs. my original rank.
Really, I wish to break the tie for the tied numbers only....the others can
simply be moved into the new ranking column. The final visual order is not
as important as the correctness of the numerical rank.
Keep up the good suggestions!
Robert. |
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Pete,Looks like this might work. I originally used an unweighted count...
Rober posted on Tuesday, October 14, 2008 8:39 AM
Pete,
Looks like this might work. I originally used an unweighted count...so the
weighted version seems to do what I need. I have 30 total rows of data to
rank this way so I do appreciate the assistance.
robert. |
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You could make a new total by adding those tie-breakers to the currenttotal.
Pete_UK posted on Tuesday, October 14, 2008 8:37 PM
You could make a new total by adding those tie-breakers to the current
total. As they operate highest to lowest, you should subtract them
from the maximum within the range, i.e.:
=3DA2 + (MAX(C$2:C$11)-C2) + (MAX(D$2:D$11)-D2) + (MAX(E$2:E$11)-E2)
Copy this down a helper column, then apply your rank formula to this.
If your tie-breakers have different weights, then you can multiply
them by some weighting factor, eg:
=3D1000*A2 + 100*(MAX(C$2:C$11)-C2) + 10*(MAX(D$2:D$11)-D2) + (MAX(E$2:E
$11)-E2)
Hope this helps.
Pete
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Well, this worked for me.
Pete_UK posted on Tuesday, October 14, 2008 8:37 PM
Well, this worked for me. With your data in A1:F11, put this in G2:
=3DIF(COUNTIF(A$2:A$11,A2)>1,(1000*A2+100*(MAX(C$2:C$11)-C2)+10*(MAX(D
$2:D$11)-D2)+(MAX(E$2:E$11)-E2))/1000,A2)
and this in H2:
=3DRANK(G2,G$2:G$11,1)
It gave the same ranks as your wish column.
Hope this helps.
Pete
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You're welcome, Robert - thanks for feeding back.
Pete_UK posted on Tuesday, October 14, 2008 8:38 PM
You're welcome, Robert - thanks for feeding back.
Pete
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